在线一元二次方程计算器实例(方程计算器在线计算)

前端技术 2023/09/05 JavaScript

复制代码 代码如下:

<html>
<head>
<meta http-equiv=\"Content-Type\" content=\"text/html\" charset=\"utf-8\">
<title>在线一元二次方程式计算器</title>
</head>
<body>
<form name=\"fquad\">
    <p align=\"center\">解二次方程式计算<br>
     </p>
    <table align=\"center\">
        <tbody>
            <tr>
                <td bgcolor=\"#990000\">
                <h2><font color=\"#ffffff\"><input size=\"4\" name=\"fa\" type=\"text\"> x<sup>2</sup>+ <input size=\"4\" name=\"fb\" type=\"text\"> x + <input size=\"4\" name=\"fc\" type=\"text\"> = 0 <input onclick=\"checkQuad()\" type=\"button\" value=\"解题\"> <input type=\"reset\" value=\"重置\"> </font></h2>
                <p align=\"center\"><font color=\"#ffffff\" face=\"Arial\"><b>一元二次方程的解法</b></font></p>
                </td>
            </tr>
            <tr>
                <td bgcolor=\"#990000\">
                <h2><font color=\"#ffffff\">x<sub><a style=\"text-decoration: none\" ><font color=\"#ffffff\">1</font></a></sub>=<input size=\"45\" name=\"x1\" type=\"text\"> <br>
                x<sub>2</sub>=<input size=\"45\" name=\"x2\" type=\"text\"> </font></h2>
                </td>
            </tr>
            <tr>

            </tr>
        </tbody>
    </table>
</form>
<p align=\"center\">Made by CRoot</p>
<script language=\"JavaScript\">
<!--
var rootparti;
var rootpart;
var det;
var rootparti1;
var rootparti2;
var a;
var b;
var c;
var x1;
var x2;
var i = \"i\";
function checkQuad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
if (a == 0 && c != 0) {
x1 = -c / b;
x2 = \"Not a quadratic equation, but here is your answer for x\";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else if (a == \"\" && c != 0) {
x1 = -c / b;
x2 = \"Not a quadratic equation\";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else {
quad();
   }
}
function quad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
det = Math.pow(b,2) - 4 * a * c;
rootpart = Math.sqrt(det) / (2 * a);
rootparti = (Math.sqrt(-det) / (2 * a)) + i;
if (parseFloat(rootparti) < 0) {
rootparti1 = rootparti;
rootparti2 = (-1 * parseFloat(rootparti)) + i;
}
else {
rootparti1 = (-1 * parseFloat(rootparti)) + i;
rootparti2 = rootparti;
}
if (rootparti1 == \"1i\") {
rootparti1 = i;
rootparti2 = \"-i\";
}
else if (rootparti1 == \"-1i\") {
rootparti1 = \"-i\";
rootparti2 = i;
}
if (det == 0) {
x1 = x2 = -b / (2 * a);
}
else if (det > 0) {
x1 = (-b + Math.sqrt(det)) / (2 * a);
x2 = (-b - Math.sqrt(det)) / (2 * a);
}
else if ((-b / (2 * a)) == 0) {
x1 = rootparti1;
x2 = rootparti2;
}
else {
x1 = (-b / (2 * a) + \" + \" + rootparti1);
x2 = (-b / (2 * a) + \" + \" + rootparti2);
}
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
// will solve for complex numbers

//   -->
</script>
</body>
</html>

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