本文实例为大家分享了C++计算每个字符出现的次数的实现代码,供大家参考,具体内容如下
#include <iostream>
//#include <cstdlib>
#include <ctime>
using namespace std;
const int NUMBER_OF_LETTERS = 26;
const int NUMBER_OF_RANDOM_LETTERS = 100;
void createArray(char []);
void displayArray(const char []);
void countLetters(const char [], int []);
void displayCounts(const int []);
int main()
{
char chars[NUMBER_OF_RANDOM_LETTERS];
createArray(chars);
cout << \"The lowercase letters are:\" << endl;
displayArray(chars);
int counts[NUMBER_OF_LETTERS];
countLetters(chars, counts);
cout << \"\\nThe occurrences of each letter are:\" << endl;
displayCounts(counts);
return 0;
}
void createArray(char chars[])
{
srand((unsigned int)time(0));
for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++)
{
chars[i] = static_cast<char>(\'a\' + rand() % (\'z\' - \'a\' + 1));
}
}
void displayArray(const char chars[])
{
for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++)
{
if ((i + 1) % 20 == 0)
cout << chars[i] << \" \" << endl;
else
cout << chars[i] << \" \";
}
}
void countLetters(const char chars[], int counts[])
{
for (int i = 0; i < NUMBER_OF_LETTERS; i++)
counts[i] = 0;
for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++)
counts[chars[i] - \'a\']++; //经典
}
void displayCounts(const int counts[])
{
for (int i = 0; i < NUMBER_OF_LETTERS; i++)
{
if ((i + 1) % 10 == 0)
cout << counts[i] << \" \" << static_cast<char>(i + \'a\') << endl;
else
cout << counts[i] << \" \" << static_cast<char>(i + \'a\') << \" \";
}
cout << endl;
}
以上就是本文的全部内容,希望对大家的学习有所帮助。
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