本文实例讲述了jQuery+JSON实现AJAX二级联动的方法。分享给大家供大家参考,具体如下:
后台Handler.ashx
<%@ WebHandler Language=\"C#\" Class=\"Handler\" %>
using System;
using System.Web;
using System.Data;
public class Handler : IHttpHandler
{
Common coObj = new Common();
public void ProcessRequest(HttpContext context)
{
if (context.Request.Params[\"n\"] != null)
{
string num = context.Request.Params[\"n\"].ToString();
context.Response.ContentType = \"text/plain\";
string str = \"select * from address where a_num2=\" + num;
DataTable dt = coObj.GetTable(str);
string json = JSONHelper.DataTableToJSON(dt);
context.Response.Write(json);
}
}
public bool IsReusable
{
get
{
return false;
}
}
}
前台dropdownlist.html
<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\"
\"http://www.w3.org/TR/html4/loose.dtd\">
<html>
<head>
<title>dropdownlit </title>
<meta name=\"Generator\" content=\"EditPlus\" />
<script type=\"text/javascript\" src=\"js/jquery-1.5.2.js\"></script>
<script type=\"text/javascript\">
$(function(){
InitData(0);
});
function InitData(n)
{
$.ajax({
type:\"POST\",
dataType:\"json\",
url: \"Handler.ashx\",
data:{\"n\":n},
success:function(json){
$.each(json,function(i,n){
var pro=$(\"#dl1\");
$(\"\"+ n.A_Name +\"\").appendTo(pro);
});
}
});
}
function GetCity(n)
{
var city=$(\"#dl2\");
city.html(\"\");
$.ajax({
type:\"POST\",
dataType:\"json\",
url: \"Handler.ashx\",
data:{\"n\":n},
success:function(json){
$.each(json,function(i,n){
$(\"\"+ n.A_Num1 +\">\"+ n.A_Name +\"\").appendTo(city);
});
}
});
}
</script>
</head>
<body>
<select id=\"dl1\" onchange=\"GetCity(this.value)\">
</select>
<select id=\"dl2\">
</select>
</body>
</html>
希望本文所述对大家jQuery程序设计有所帮助。
本文地址:https://www.stayed.cn/item/3621
转载请注明出处。
本站部分内容来源于网络,如侵犯到您的权益,请 联系我