PHP日期函数date格式化UNIX时间的方法

前端技术 2023/09/02 PHP

本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下：

日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出

使用到函数语法如下

string date (string $Format);
string date (string $Format, int $Time);

下面是演示代码

<?php
echo \"When this page was loaded,\\n\";
echo \'It was then \', date (\'r\'), \"\\n\";
echo \'The currend date was \', date (\'F j, Y\'), \"\\n\";
echo \'The currend date was \', date (\'M j, Y\'), \"\\n\";
echo \'The currend date was \', date (\'m/d/y\'), \"\\n\";
echo \'The currend date was the \', date (\'jS \\o\\f M, Y\'), \"\\n\";
echo \'The currend time was \', date (\'g:i:s A T\'), \"\\n\";
echo \'The currend time was \', date (\'H:i:s O\'), \"\\n\";
echo date (\'Y\');
date (\'L\')?(print \' is\'):(print \' is not\');
echo \" a leap year\\n\";
echo time (\'U\'), \" seconds had elapsed since January 1, 1970.\\n\";
?>

输出结果如下

It was then Sat, 26 Dec 2009 07:09:51 +0000
The currend date was December 26, 2009
The currend date was Dec 26, 2009
The currend date was 12/26/09
The currend date was the 26th of Dec, 2009
The currend time was 7:09:51 AM GMT
The currend time was 07:09:51 +0000
2009 is not a leap year
1261811391 seconds had elapsed since January 1, 1970.

希望本文所述对大家的php程序设计有所帮助。

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